328.md

328. Odd Even Linked List

难度: Medium

刷题内容

原题连接

• https://leetcode.com/problems/odd-even-linked-list/

内容描述

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes.

You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.

Example 1:

Input: 1->2->3->4->5->NULL
Output: 1->3->5->2->4->NULL
Example 2:

Input: 2->1->3->5->6->4->7->NULL
Output: 2->3->6->7->1->5->4->NULL
Note:

The relative order inside both the even and odd groups should remain as it was in the input.
The first node is considered odd, the second node even and so on ...

解题方案

思路 1 - 时间复杂度: O(N) - 空间复杂度: O(1)

画个图很容易写，beats 32.52%

class Solution:
    def oddEvenList(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        if not head or not head.next or not head.next.next:
            return head
        
        odd = head
        dummy_even = even = head.next
        while even and even.next:
            odd.next = even.next
            odd = odd.next
            even.next = odd.next
            even = even.next
        odd.next = dummy_even
        return head